If A + B = 90°, sin A = a and sin B = b then prove that a^2 + b^2 = 1.
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HEY MATE!!!
HERE IS YOUR SOLUTION
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
_______$ølution_______
Given:- A + B = 90°
SINA = a
SINB = b
Prove that:- a² + b² = 1
PROOF:-
A + B = 90°
A = 90° - B
take LHS....
a² + b²
= SIN²A + SIN²B
= SIN²(90° - B) + SIN²B. [ SIN(90°- ø) = COSØ]
= COS²B + SIN²B. [ SIN²B + COS²B = 1]
= 1
LHS = RHS = 1
HENCE PROVED....
HOPE IT HELPS UH A LOT✴✴
HERE IS YOUR SOLUTION
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
_______$ølution_______
Given:- A + B = 90°
SINA = a
SINB = b
Prove that:- a² + b² = 1
PROOF:-
A + B = 90°
A = 90° - B
take LHS....
a² + b²
= SIN²A + SIN²B
= SIN²(90° - B) + SIN²B. [ SIN(90°- ø) = COSØ]
= COS²B + SIN²B. [ SIN²B + COS²B = 1]
= 1
LHS = RHS = 1
HENCE PROVED....
HOPE IT HELPS UH A LOT✴✴
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