Math, asked by sauveerdixit, 1 year ago

If A + B = 90°, sin A = a and sin B = b then prove that a^2 + b^2 = 1.

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Answered by Anonymous
11
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Answered by Anonymous
13
HEY MATE!!!

HERE IS YOUR SOLUTION

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_______$ølution_______

Given:- A + B = 90°

SINA = a

SINB = b

Prove that:- a² + b² = 1


PROOF:-

A + B = 90°

A = 90° - B

take LHS....

a² + b²

= SIN²A + SIN²B

= SIN²(90° - B) + SIN²B. [ SIN(90°- ø) = COSØ]

= COS²B + SIN²B. [ SIN²B + COS²B = 1]

= 1

LHS = RHS = 1

HENCE PROVED....


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