Question

If A+B=90°,then sin²A+sin²B=​

Answer 1

Answer:

1

Step-by-step explanation:

A+B=90°

sin²A+sin²B

sin²A+sin²(90-A)

sin²A+cos²A. (sin(90-Φ)=cosΦ)

1

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Answer 2

Answer:

the answer is 1

Step-by-step explanation:

A+B=90°

A=90°-B

Now,

sin^2(A) + sin^2(B) {putting the value of A}

= sin^2(90-B) + sin^2(B) {sin(90-theta)= cos(theta)

= cos^2(B) +sin^2(B) {sin^2(theta) +cos^2(theta)=1}

=1