if A+B=90degrees show that sinA=cosB
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Answered by
6
Hi !
A + B = 90° (given )
A = 90° - B
taking sin both side
we get ,
sinA = sin ( 90° -B)
sinA = cosB , [°•° sin(90° - ¢ ) = cos¢]
since prooved ♻ sinA = cosB
________________________
Hope this helps you !!
@Rajukumar111
A + B = 90° (given )
A = 90° - B
taking sin both side
we get ,
sinA = sin ( 90° -B)
sinA = cosB , [°•° sin(90° - ¢ ) = cos¢]
since prooved ♻ sinA = cosB
________________________
Hope this helps you !!
@Rajukumar111
Answered by
1
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