If a -b,a,a+b are the zeroes of polynomial x3-6x2 +8x
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Step-by-step explanation:
sum: a+b+a-b= 2a
product:(a+b)(a-b)= a2-b2
sum=-b/a=2a
a=1,b=-6,c=8
2a=6/1
a=3
a2-b2=8
3square-b2=8
9-b2=8
b2=1
b=1
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