Question

if (a+b),a,(a-b) are the zeros of polynomial 2x cube - 6x square + 5x-7 . find value of a

Answer 1

Hello friends!!!

Here is your answer :

$p(x) = 2 {x}^{3} - 6 {x}^{2} + 5x - 7$

( a + b ), ( a ), ( a - b ) are the Zeroes of p(x).


As we know,

$sum \: \: of \: \: zeroes \: = \frac{ - b}{a}$


$a + b + a + a - b = \frac{ - ( - 6)}{2}$


$3a = \frac{6}{2}$


$3a = 3$


$a = 1$



Therefore, value of a is 1 .


Hope it helps you...

☺️☺️☺️☺️

# Be Brainly

Answer 2

$Heya$‼


Since, $( a + b ) , a \:and\:( a - b )$ are the zeroes of given polynomial.


Given that, $p(x)=2x^3-6x^2+5x-7$


As we know ,

$Sum\:of\:the\:zeroes$
$= - Coefficient\:of\:x^2 / Coefficient\:of\:x^3$

$(a+b)+a+(a-b)$ $= -(-6) / 2$

$3a = 3$

$a=3/3$

$a = 1$