Question

if a-b,a and a+b are the zeroes of the polynomial f(x) = 2(x)^3-6(x)^2+5a-7 . Then find the value of a.​

Answer 1

Answer:

Step-by-step explanation:

Answer:

Value of a=1

Step-by-step explanation:

Given is a-b, a and a+b are the zeroes of the polynomial f(x)=2x^{3}-6x^{2}+5x-7, then

sum of zeroes=\frac{-coefficient of x^{2}}{coefficient of x^{3}}

a-b+a+a+b=\frac{6}{2}

3a=3

a=1

Thus, the  value of a is equal to "1"