Question

 If a – b, a and a + b are zeroes of the polynomial fix) = 2x³ – 6x² + 5x – 7, then value of a is * 1 2 -5 7​

Answer 1

Answer:

a=1

Step-by-step explanation:

sum of roots = a-b+a+a+b=3a=-(-6)/2

3a=3

a=1

Answer 2

(a – b), a, (a + b) are the zeros of 2x3 – 6x2 + 5x – 7

Sum of zeros = -(coefficient of x)/(coefficient of x2)

a – b + a + a + b = -(-6) / 2 = 3

a = 1

Ans - 1