If a - b , a and a + b are zeroes of the polynomial x ^ 3 - 15x ^ 2 + 71x - 105 Then find a and b.
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Step-by-step explanation:
As the zeroes are in AP, let the zeroes be a-d, a, a+d.
The sum of zeroes of the given polynomial is -(-15)/1 = 15.
Therefore, a-d + a + a+d=15. Hence, a = 5.
Also, the product of zeroes is -(-105)/1 = 105.
Therefore, 5(5-d)(5+d)=105, or 25 - d^2 = 21.
Then, d^2 = 4. Hence, d=+-2.
Therefore, the zeroes are 3, 5, 7.
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