Question

if a-b a and a+b are zeroes of x³-3x²+x+1 then a²+b² will be? a. 3 b. 4 c. 5 d.2​

Answer 1

Answer:

5

Step-by-step explanation:

Clearly, sum of the roots is,

a+(a-b)+(a+b)= -(-3)/1=3

=> 3a= 3

=> a= 1.

Again, product of roots is,

a(a-b)(a+b)= -1/1= -1

=>(1-b)(1+b) = -1 [since, a=1]

=> 1- b^2 = -1

=> b^2 = 2

a²+b²=4+1=5

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