If (a-b):(a+b)=1:11 find the ratio (5a+4b+15):(5a-4b+3)
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49
given,
( a - b)/(a + b) = 1/11
in LHS divide by b both nominator and dinominator.
=>(a/b - b/b)/(a/b + b/b) = 1/11
=> (a/b -1)/( a/b + 1)=1/11
=> 11(a/b) -11 =a/b + 1
=>10(a/b) =12
a/b =6/5
5a=6b
let a =6k
b= 5k
now,
=> (5a + 4b +15)/(5a -4b +3) =?
=>{ 5(6k) + 4(5k) +15}/{5(6k)-4(5k)+3}
=>(30k +20k +15)/(30k-20k +3)
=>(50k+15)/(10k+3)
=>5(10k+3)/(10k+3)
5 : 1 (answer)
( a - b)/(a + b) = 1/11
in LHS divide by b both nominator and dinominator.
=>(a/b - b/b)/(a/b + b/b) = 1/11
=> (a/b -1)/( a/b + 1)=1/11
=> 11(a/b) -11 =a/b + 1
=>10(a/b) =12
a/b =6/5
5a=6b
let a =6k
b= 5k
now,
=> (5a + 4b +15)/(5a -4b +3) =?
=>{ 5(6k) + 4(5k) +15}/{5(6k)-4(5k)+3}
=>(30k +20k +15)/(30k-20k +3)
=>(50k+15)/(10k+3)
=>5(10k+3)/(10k+3)
5 : 1 (answer)
mysticd:
abhi , do the small corrections
numerator
4th line from last in denominator 30k
remove implies symbol put =
last line = 5:1
but time is over
thank you .
u'r not changed completely
read my comments
sorry i wrote nominator in place of numerator
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