Question

If A^→⋅B^→+|A→×B→|=√2AB , find the value of θ .

Answer 1

Explanation:

We know that,

A.B=ABcosθ Given : ∣A×B∣= 3 A.BUsing

∣A×B∣=ABsinθA.B=∣A∣∣B∣cosθ∴ ABsinθ= 3 ABcosθtanθ= 3

⟹θ=60 o Now (A+B)2 =A 2 +B 2 +2AB× 21 =A 2 +B 2 +ABor ∣A+B∣=(A 2 +B 2 +AB) 1/2

Hope this will help you buddy...