If A*B = A + B + A^2B^3 - A^3B^2, find the value of 1*2.
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Answered by
0
Answer:
Step-by-step explanation:
[
8
−1
1
10
2
−1
]
Since, 2A+3B=[
2
3
−1
2
4
5
] …………(1)
A+2B=[
5
1
0
6
3
2
] ………….(2)
2× Equation (2)− Equation (1)
⇒2A+4B−2A−3B=[
10−2
2−3
0+1
12−2
6−4
4−5
]
⇒B=[
8
−1
1
10
2
−1
][
8
−1
1
10
2
−1
]
Since, 2A+3B=[
2
3
−1
2
4
5
] …………(1)
A+2B=[
5
1
0
6
3
2
] ………….(2)
2× Equation (2)− Equation (1)
⇒2A+4B−2A−3B=[
10−2
2−3
0+1
12−2
6−4
4−5
]
⇒B=[
8
−1
1
10
2
−1
]
Answered by
0
Step-by-step explanation:
your answer shoud be -1 not sure
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