if a-b, a+b are the zeros of x^2-4x+3 then (a, b) =
A) (3, 1)
B) (-3,-1)
C) (2, 1)
D) (-2,-1)
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Answer:-
(Let a = α & b = β).
Given:
α - β , α + β are the zeroes of x² - 4x + 3.
On comparing with standard form of a quadratic equation i.e., ax² + bx + c = 0 ;
Let ;
- a = 1
- b = - 4
- c = 3.
We know that,Sum of the zeroes = - b/a
⟹ α - β + α + β = - ( - 4)/1
⟹ 2α = 4
⟹ α = 4/2
⟹ α = 2
And,
Product of the zeroes = c/a
⟹ (α - β) * (α + β) = 3/1
- (a + b) * (a - b) = a² - b².
⟹ α² - β² = 3
Putting the value of α we get,
⟹ (2)² - β² = 3
⟹ 4 - 3 = β²
⟹ 1 = β²
⟹ √1 = β
⟹ 1 = β
∴(a , b) = (α , β) = (2 , 1). (Option - C).
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