Question

If |A^ - B^ | = |A^ | = |B^| find angle between A & B

Answer 1

Step-by-step explanation:

Formula for vector subtraction is A^ - B^ = √(A² +B²-2ABcosθ)    where θ is angle between them

It is given that A^ - B^=|A^ | = |B^| so lets convert the formula in terms of |A^ |

A^ - B^ = |A^ | and also |B^| =|A^ |  

Therefore

|A^ | = √ (A² +A² -2A²cosθ

on squaring both the sides

A² = 2A² -2A²cosθ and on rearranging

A² =2A²cosθ

or  cosθ  =1/2

hence θ =60 degree or $\pi$/3 radian

hope it helps you

please please mark it brainliest

Answer 2

Answer:

Formula for vector subtraction is A^ - B^ = √(A² +B²-2ABcosθ)    where θ is angle between them

It is given that A^ - B^=|A^ | = |B^| so lets convert the formula in terms of |A^ |  

A^ - B^ = |A^ | and also |B^| =|A^ |    

Therefore  

|A^ | = √ (A² +A² -2A²cosθ

on squaring both the sides  

A² = 2A² -2A²cosθ and on rearranging  

A² =2A²cosθ  

or  cosθ  =1/2  

hence θ =60 degree or /3 radian  

Step-by-step explanation:

Plz mark as brainliest..