Question

If |A×B|=|A.B|, find the angle between And B​

Answer 1

So

|A.B| = A.B Cos theta ............( dot product of two vectors)

|AxB| = A.B Sin theta ............( cross product of two vectors)

Given

|A×B|=|A.B|

A.B Sin theta = A.B Cos theta

Sin theta = Cos theta

When theta = 45 degrees value of sin theta and cos theta are equal= $\frac{1}{\sqrt{2}}$

So the angle between A and B is 45 degrees

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