if A*B=A.B then find angle between AandB
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A x B =lAl lBl sinΦ
A x B =lAl lBl sinΦSin Φ = A x B/ A.B
A x B =lAl lBl sinΦSin Φ = A x B/ A.B¤=90°
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Answer:
A× B = A.B
ABsin theta = ABcos theta
Sin theta = cos theta
tan theta = 1
Then
theta = 45°
Angle between A and B is 45°.
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