If a, b&c are interior angle of a triangle ABC then show that.
Sin(B+C)/2=cosA/2
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in a triangle ABC
angle A+ angle B + angle C = 180°
angle B + angle C= 180 - angle A
taking LHS
sin(B+C)/2
sin( 180- A)/2
sin(180/2 -A/2)
sin(90-A/2). ( sin90 -Q = cosQ)
cos(A/2)
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