Question

if a≠b and a^2-b^2/9= a+b, then what is the value of a-b?

Answer 1

Answer:

(C) 9

Step-by-step explanation:

Replace a^2-b^2 with (a+b)(a-b)

Therefore, (a+b)(a-b)/9=a+b

or, (a-b)/9=1

or,a-b=9

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Answer 2

Step-by-step explanation:

a²-b²/9=a+b

[applying the formula a²-b²=(a+b) (a-b)]

(a+b) (a-b) /9=(a+b)

(cancelling a+b from both sides)

a-b/9=1

a-b=9