Math, asked by Raquelitaaaa861, 1 year ago

If (a-b) and (a+b) are the zeros of the polynomial f(x) =2x³-6x²+5x-7.find the value of a

Answers

Answered by HimaniVarshney
9
most probably answer is...==
we know that
sum of zeroes=-b/a
a-b+a+b=-(-6 )/2
2a=3
a=3/2
Answered by ishanisooraj
2

Answer:

a = 1

Step-by-step explanation:

Given----> ( a - b ) , a and ( a + b ) are zeroes of

f ( x ) = 2x³ - 6x² + 5x - 7

To find ----> Value of a

Solution-----> We know that ,

If a cubic polynomial

p ( x ) = ax³ + bx² + cx + d , and its zeroes are α , β , γ , then ,

α + β + γ = - Coefficient of x² / Coefficient of x³

Now , ATQ,

( a - b ) , a , ( a + b ) are zeroes of

f ( x ) = 2x³ - 6x² + 5x - 7

Now , we know that ,

Sum of zeroes = -Coefficient of x²/Coefficient ofx³

( a - b ) + a + ( a + b ) = - ( -6 ) / 2

=> 3a = 3

=> a = 3 / 3

=> a = 1

Additional information------>

1) If , p ( x ) = ax³ + bx² + cx + d , and its zeroes are α , β and γ .

α + β + γ = - Coefficient of x² / Coefficient of x³

αβ + βγ + yα = Coefficient of x / Coeficient of x³

α β γ = - Constat term / Coefficient of x³

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