Math, asked by anu2589, 10 months ago

If (a-b) and (a+b) are zeroes of the polynomial f(x)=2x^3-6x^2+5x-7 find the value of a​

Answers

Answered by TheOxford
0
The given Polynomial has <b>3</b> zeroes.




<b>Step I :</b> <u>Assumption</u>

Let <b>( a - b ), a & ( a + b ) </b> be the zeroes.




<b>Step II :</b> <u>Determine a, b, c and d.</u>

f ( x ) = 2x³ - 6x² + 5x - 7

On comparing with ax³ + bx² + cx + d, we get

a = 2, b = - 6, c = 5, d = - 7




<b>Step III :</b> <u>Determine the value of a by sum of zeroes.</u>

<u>Sum of zeroes = - b / a</u>

Also, Sum of zeroes = ( a - b ) + a + ( a + b )

\therefore

- b / a = ( a + b ) + a + ( a - b )

- ( - 6 ) / 2 = 3a

3 = 3a

a = 3 / 3 = 1




Hence, <u>the value of a is</u> <u><I><b> 1.</b></u></I>
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