If (a-b) and (a+b) are zeroes of the polynomial f(x)=2x^3-6x^2+5x-7 find the value of a
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The given Polynomial has zeroes.
Let be the zeroes.
f ( x ) = 2x³ - 6x² + 5x - 7
On comparing with ax³ + bx² + cx + d, we get
a = 2, b = - 6, c = 5, d = - 7
Also, Sum of zeroes = ( a - b ) + a + ( a + b )
- b / a = ( a + b ) + a + ( a - b )
- ( - 6 ) / 2 = 3a
3 = 3a
a = 3 / 3 = 1
Hence,
Let be the zeroes.
f ( x ) = 2x³ - 6x² + 5x - 7
On comparing with ax³ + bx² + cx + d, we get
a = 2, b = - 6, c = 5, d = - 7
Also, Sum of zeroes = ( a - b ) + a + ( a + b )
- b / a = ( a + b ) + a + ( a - b )
- ( - 6 ) / 2 = 3a
3 = 3a
a = 3 / 3 = 1
Hence,
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