Question

If (a-b) and ab are 6 and 40 find a2+b2 and (a+b)2

Answer 1

Answer:

(a-b)=6

ab=40

(square both side)

(a-b)^2=6^2

a^2+b^2-2ab=36

a^2+b^2-2*40=36

a^2+b^2-80=36

a^2+b^2=36+80

a^2+b^2=116

(a+b)^2=a^2+b^2+2ab

(a+b)^2=116+2*40

(a+b)^2=116+80

(a+b)^2=196