Question

If a, b and c age is 93.and 10 years ago their age is 2:3:4 .then what is the present age of b.

Answer 1

Sum of present ages = 93

10years ago, sum of their ages = 93 - (10+10+10) = 93 - 30 = 63 years.

10 years ago the ratio of age is 2:3:4

Let their ages were 2x, 3x and 4x

2x + 3x + 4x = 63

=> 9x = 63

=> x = 63/9

=> x = 7

10years ago, B's age = 7×3 = 21

B's present age = 21+10 = 31 years

Answer 2

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Sum of present ages = 93

10years ago, sum of their ages = 93 - (10+10+10) = 93 - 30 = 63 years.

10 years ago the ratio of age is 2:3:4

Let their ages were 2x, 3x and 4x

2x + 3x + 4x = 63

=> 9x = 63

=> x = 63/9

=> x = 7

10years ago, B's age = 7×3 = 21

B's present age = 21+10 = 31 years.

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