Question

if a b and c are constants is a(x-b)-c=ax-(ab+c)

Answer 1

Answer:

Yes, a(x-b)-c=ax-(ab+c)

Step-by-step explanation:

a(x-b)-c=ax-(ab+c)

Simplify the bracket

let's solve a(x-b)-c first

a(x-b)-c ⇒ a × x - a × b - c

⇒ ax - ab - c

let's now simplify ax-(ab+c)

ax - ( ab + c)

open the bracket with ( - )

ax - ab - c

So, a(x-b)-c is equivalent to  ax-(ab+c)

Hope this helps my friend.

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Answer 2

Answer:

Yes, a(x-b)-c=ax-(ab+c)

Step-by-step explanation:

a(x-b)-c=ax-(ab+c)

Simplify the bracket

let's solve a(x-b)-c first

a(x-b)-c ⇒ a × x - a × b - c

⇒ ax - ab - c

let's now simplify ax-(ab+c)

ax - ( ab + c)

open the bracket with ( - )

ax - ab - c

So, a(x-b)-c is equivalent to  ax-(ab+c)