If a, b and c are in A.P. a+b+c=15 find a,b,c
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A,7,b,23,c are in AP
let the common difference = d
b-7 = d----(1)
23-b = d---(2)
add (1) and (2)
16 = 2d
2d = 16
∴d=16/2= 8
i) d= 7-a
8=7-a⇒8-7 =-a
1= -a
∴a= -1
ii) b-7=d
b-7=8
b=8+7
b=15
iii)c-23=d
c-23=8
c=8+23
c=31
∴a =-1, b=15, c=31.......☺
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