If a, b and c are in A.P. then (a) a=b+c 2a=b+c2 (b) B= a+c 2b=a+c2 (c) C=a+b 2c=a+b2 (d) B=a+c b=a+c
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Given that a,b,c are in A. P.
⇒2b=a+c……. (1)
And a
2
,b
2
,c
2
are in H. P.
b
2
1
−
d
2
1
=
c
2
1
−
b
2
1
b
2
a
2
(a–b)(a+b)
=
b
2
c
2
(b–c)(b+c)
ac
2
+bc
2
=a
2
b+a
2
c[∵a–b=b–c]
ac(c–a)+b(c–a)(c+a)=0
(c–a)(ab+bc+ca)=0
either c–a=0orab+bc+ca=0
either c=a or (a+c)b+ca=0 and then form (i) 2b
2
+ca=0
Either a=b=c or b
2
=a
2
−c
i.e. a,b,
2
−c
are in G. P. Hence Proved
explain: please mark as brainlist....
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