if a b and c are in continued proportion. (I)(a+b)(b+c)-(a+c)(b+d)=(b-c)2. (ii) ( a-b/c +a-c/b)^2 - (d-b/c + d-c/b)= (a-d)2 (1/C2 - 1/b2). pls help
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since A,B,C and D are in continued proportion.
therefore
the left hand side of the equation is:
since from (1)
hence L.H.S.=
hence proved.
therefore
the left hand side of the equation is:
since from (1)
hence L.H.S.=
hence proved.
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