if a b and c are Interior angles of a triangle abc then cos (b+c2) is equal to a)sin a/2 b)-sin a/2 c)cos a/2 d)-cos a/2
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If A, B and C are interior angles of a triangle ABC, then show that sin((B+C)/2)=cos(A/2). ∴cosA2=sin(B+C2)=L. H.
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