Math, asked by sakshi5412, 11 months ago

if a b and c are interior angles of a triangle ABC then show that Cos A + B upon 2 is equals to sin C upon 2 ​

Answers

Answered by Sidmaths
8

Answer:

we know that sum of angles of a triangle = 180

A+B+C =180

A+B = 180-C

divide the above equation by 2

= (A+B)/2 = (180-C)/2

(A+B)/2 = (90-C/2)

multiply the above equation by cos on both sides

cos (A+B/2) = cos(90-C/2)

as we know cos (90-x) = sin x

therefore cos A+B/2 = sin C/2

hope it helps.

Answered by kamlasawanth9793
0

Answer:

acha question hai excellent

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