if a, b and c are interior angles of a triangle ABC, then show that : tan(b+c/2) = cot a/2
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⇒ (A + B + C) = 180°
⇒ (A + B) = 180˚ – C
⇒ (A + B)/2 = 90˚ – C/2
• Taking tan on both sides, we get
↠ tan (A + B)/2 = tan(90˚ - C/2)
= cot C/2
Hence proved.
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