Question

If A, B and C are interior angles of a triangle ABC, then show that sin [(B + C)/2] = cos A/2.

No Spam❌
No irrelevant answers❌

but i hate you... ​

Answer 1

Answer:

$\frac{5}{ |2| 2} 8851y2)5150ffufuuffuf\% log_{ log( \tan( \cot( \csc( \csc( \binom{\%\%\%\%20 \sqrt[ \sqrt[ \sqrt{ \sqrt{ | < > \times = | } } ]{?} ]{?} }{?} ) ) ) ) ) }(?)$

Step-by-step explanation:

please mark me as brainlist