Math, asked by SHIVAMDHASMANA, 1 month ago

If A, B and C are interior angles of a triangle ABC, then show that sin [(B + C)/2] = cos A/2.

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Answers

Answered by IIAKASHII
5

Answer:

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Answered by anshultiwari327
1

Answer:

sin(45+45) /2=cos90/2

Step-by-step explanation:

according to question:

A, B, C are interior angle of a triangle

then, A+B+C=180

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