Question

if a b and c are interior angles of triangle ABC then show that sin b + c / 2 =Cos A /2​

Answer 1

Answer:

Refer attachment...........

Answer 2

Answer:

 Sin[(B+C)/2]

 Sin[(B+C)/2]Since A+B+C=180 for interior angles of triangle ABC.

 Sin[(B+C)/2]Since A+B+C=180 for interior angles of triangle ABC.then B+C=180-A.

I hope you can help