Question

If a,b and c are non zero real number such that ab=2(a+b),bc=3(b + c) and ca=4(c+a) then value of 5a+7b+c is​

Answer 1

Step-by-step explanation:

Given that

ab−2(a+b)⇒

a

1

+

b

1

=

2

1

bc=3(b+c)⇒

b

1

+

c

1

=

3

1

ca=4(c+a)⇒

c

1

+

a

1

=

4

1

(

c

1

+

a

1

)−(

a

1

+

b

1

)=

3

1

−

2

1

c

1

−

a

1

=

6

−1

c

1

+

a

1

+

c

1

−

a

1

=

4

1

−

6

1

c

2

=

12

1

⇒c=24

a

1

=

4

1

−

24

1

⇒a=

5

24

b

1

=

2

1

−

4

1

⇒b=

7

24

5a+7b+c=24+24+24

=72