Question

If a,b and c are real numbers such that a lesser and equal to b , c greater than 0 , then AC=?​

Answer 1

Answer:

Here's a proof by contrapositive. If bc<ac, then 0<ac-bc=(a-b)c. We have two numbers multiplying to equal a positive number, so they are either both positive or both negative. That is:

(a-b>0 and c>0) or (a-b<0 and c<0). Adding b to both sides in the first inequality of each case gives (a>b and c>0) or (a<b and c<0). Examining both cases, it cannot be the case that a>b and c<0. Therefore by contrapositive, a>b and c<0 implies bc>ac.

Step-by-step explanation:

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