If A, B and C are the angle of a ∆ABC, prove that tan(C+A/2)= cotB/2
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Step-by-step explanation:
A,B,C are the angle
A+B+C=180
A+C=180-B
A+C/2=180-B/2
A+C/2=90-B/2
tan(A+C/2)=tan(90-B/2)
tan(A+C/2)=cotB/2
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