if a b and c are the angle of triangle ABC prove that tan (C+A/2)=cot B/2
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if a b and c are the angle of triangle ABC
a+b+c=180
c+a=180-b
tan [(c+a)/2]=tan [(180-b)/2]
=tan (90-b/2)
=cot b/2
a+b+c=180
c+a=180-b
tan [(c+a)/2]=tan [(180-b)/2]
=tan (90-b/2)
=cot b/2
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