If A,B and C are the interior angles of a triangle,then prove that cosec 2 (B+C /2) - tan 2 A/2 = 1.
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cosec 2(B+C/2) = sec 2 A/2 as A+B+C/2 = 90
sin 90 --A/2 = cos A/2 SO
sec 2 A/2 -- tan 2 A/2 = 1
sin 90 --A/2 = cos A/2 SO
sec 2 A/2 -- tan 2 A/2 = 1
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