Question

If A, B and C are the interior angles of triangle ABC, find tan{b+c/2}

Answer 1

a+b+c = 180  (dividing by 2 on LHS and RHS)
a/2+b/2+c/2 = 90
b+c/2 = 90-a/2
tan(b+c/2) = tan(90 - a/2)
tan(b+c/2) = cot a/2     [tan (90 - Ф) = cotФ]

hope it helped u!!

Answer 2

Answer:

a+b+c = 180  (dividing by 2 on LHS and RHS)

a/2+b/2+c/2 = 90

b+c/2 = 90-a/2

tan(b+c/2) = tan(90 - a/2)

tan(b+c/2) = cot a/2     [tan (90 - Ф) = cotФ]

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