Question

if A,B and c are the interior angles of triangle ABC the sec(B+C-A/2)=​

Answer 1

Answer:

110°

Step-by-step explanation:

We know that

Sum of angles of a

triangle is 180°

So, A + B +C = 180°

= the measure of each angle is

= 180°/3 (Because there are only three points in a triangle)

= 60°

Therefore,

A=60°

B=60°

C=60°

So, the sec is = (B+C-A/2)

= (60+60-60/2)

= (120-30)

= 110°

I hope it will help you

Answer 2

Answer:

Step-by-step explanation:

sec(B+C-A/2)

sec(B+C+A-3A/2)

=sec(180-3A/2)

= -sec3A/2