Math, asked by pp7914970, 9 months ago

if a,b and c are the lengths of there sides of a triangle, them option a. a+b>c b. a-b>c c.a+b=C d.a-b=c​

Answers

Answered by itsbrainlybiswa
2

Answer:A,B and C are in arithmetic progression

⇒B=  

2

A+C

​  

 

⇒2B=A+C .......... (1)

A+B+C=180  

o

 ...... (2) [Property of triangle]  

From (1) and (2), we get

B=60  

o

 

∴  

c

a

​  

sin2C+  

a

c

​  

sin2A=  

sinC

sinA

​  

2sinCcosC+  

sinA

sinC

​  

2sinAcosA

  =2sinAcosC+2sinCcosA

  =2sin(A+C)=2sinB=2×  

2

3

​  

 

​  

=  

3

Step-by-step explanation:

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