Question

If A, B and C are three angles of a triangle and cot(B+C) =1/√3 then angle A is of​

Answer 1

Answer:

In ΔABC , A+B+C=180

⟹A+B=180

−C

⟹cot(A+B)=cot(180

−C)

cotA+cotB

cotA.cotB−1

=−cotC

⟹cotA.cotB−1=−cotA.cotC−cotB.cotC

⟹cotA.cotB+cotB.cotC+cotC.cotA=1