Question

If A, B and C are three natural numbers less than 11. The arithmetic mean of A and B is 9 and the geometric mean of B and C is 6√2. What are the values of A,B and C respectively.​

Answer 1

Answer:

please follow me and make me as brainlist.

Answer 2

Answer:

a=9, b=9, c=8

Step-by-step explanation:

The question is actually incomplete because there can be several soln of (a,b,c)

$( \frac{a + b}{2} ) = 9 \\ a + b = 18$

Also,

$bc = {(6 \sqrt{2)}^{2} } = 72$

So, by hit and trial, b should be a multiple of 3 and be less than 11, so let's take it 9.

$b = 9 \\ a = 18 - 9 = 9 \\ c = 72 \div 9 = 8$

Hence (a,b,c)=(9,9,8)