Question

If a,b and c are three natural numbers such that abc= 3600 , HCF(a,b,c)= 2, HCF(a,b) =10, HCF(b,c)=2 and HCF(a,c)=6 then what is LCM(a,b,c) equal to??

Answer 1

abc =  3600

         HCF(a,b,c) = 2

         HCF(a,b) = 10 = 2x5

         HCF(b,c) = 2 = 2

         HCF(a,c) = 6 = 2x3

LCM = Lowest common Multiple = highest power of each factors

Factors of a = 2*2*3*5

Factors of b = 2*5

Factors of c = 2*3

LCM = 2*2*3*5

LCM = 60