If a,b and c are three natural numbers such that abc= 3600 , HCF(a,b,c)= 2, HCF(a,b) =10, HCF(b,c)=2 and HCF(a,c)=6 then what is LCM(a,b,c) equal to??
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HCF (a, b, c) = 2
HCF (a, b) = 10
HCF (b, c) = 2
HCF (a, c) = 6
abc = 3600
Formula :
LCM ( a, b, c) = {abc × HCF (a, b, c)} ÷ {HCF (a, b) × HCF (a, c) × HCF (b, c)}
Substituting the values in the formula
(3600 × 2) ÷ ( 10 × 2 × 6)=
7200/120 = 60
LCM (a, b, c) = 60
HCF (a, b) = 10
HCF (b, c) = 2
HCF (a, c) = 6
abc = 3600
Formula :
LCM ( a, b, c) = {abc × HCF (a, b, c)} ÷ {HCF (a, b) × HCF (a, c) × HCF (b, c)}
Substituting the values in the formula
(3600 × 2) ÷ ( 10 × 2 × 6)=
7200/120 = 60
LCM (a, b, c) = 60
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