if A, B and C are three points on a line and B lies between A and C then,prove that AB+BC=AC
Answers
Answered by
1
Answer:
your answer is in above picture
Attachments:
Answered by
1
Answer:
Let A, B, and C be three distinct points of a line, with the respective coordinates x, y, and z. If x < y < z, then A-B-C.
Proof, By the ruler postulate:
AB= ly- xl
BC= lz - yl
AC= lx - xl
But y-x is positive because x < y; similarly, z-y and z-x are positive. So:
AB = y-x
BC = z-y
AC = z-x
Finally:
AB + BC = (y - x) + (z - y)
= z-x
=AC.
Since AB + BC = AC, A-B-C by the definition of between.If A, B and C are three points on a line, and B lies between A and C.
Similar questions