If A, B and C are three rational numbers such that 85C-A0A = 109,425 A+ 85 B - 145, thes the sum of A, B and C is divisible by a 3 b.6 c7 d. 9
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If A, B and C are three rational numbers such that 85 C - 340 A = 109, 425 A+ 85 B = 146, then the sum of A, B and C is divisible by a 3 b.6 c 7 d 9
- • Given equations are
- • 85 c – 340 a = 109 and 425 a + 85 b = 146
- • Now we need to find the sum of a,b and c.
- • So adding both the equations we get
- • 85 c – 340 a = 109
- • 85 b + 425 a = 146
- • Adding both the equations we get
- • So we get 85 b + 85 c + 85 a = 255
- • 85 (a + b + c) = 255
- • Or a + b + c = 255 / 85
- • Or a + b + c = 3
- • Now sum will be divisible by 3
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