If A, B and C represent digits from 1 to 9 such that 1 AB +CCA=697 and there is no carry–over in addition. Find the value of A+B+C
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Given : A, B and C represent digits from 1 to 9 such that 1 AB +CCA=697 and there is no carry–over in addition
To find : value of A+B+C
Solution:
1 A B
+ C C A
______
6 9 7
As there is no carry–over in addition.
B + A = 7
A + C = 9
1 + C = 6 => C = 5
A + C = 9 => A + 5 = 9 => A = 4
B +A = 7 => B + 4 = 7 => B = 3
A = 4
B = 3
C = 5
A + B + C = 4 + 3 + 5 = 12
143
+ 554
______
697
A + B + C = 12
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