If a b and c to gather can finish a piece of work in 6 days ,a alone in 12 days b in 18 days then c alone do it
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days taken by a = 12 days
a's one day work = 1/12
days taken by b = 18 days
b's one day work = 1/18
let c's one day work = x
days taken by a,b and c together = 6 days
a, b and c together one day work = 1/6 = (1/12)+(1/18)+x
⇒x =(1/6)-(1/12)-(1/18)
∴x = (6-3-2)/36
= 1/36
∵c's 1 day work = 1/36
∴c will complete the work = 36 days.
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