If a,b and c together can finish a piece of work in 4 days , a alone in 12 days and b in 18 days, then c alone can do it in
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15
t think so but answer will wrong also 10 days
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46
1/4 = 1/12 + 1/18 + 1/c
c = 9 days
take total work as 1
work done by a in one day =( total work/total number of days taken) = 1/a = 1/12.
similarly work done by b and c are 1/b = 1/18 and 1/c respectively.
total work done by all three in one day = 1/12 + 1/18 + 1/c
(work done in one day × total number of days = total work )
[1/12 + 1/18 + 1/c] ×4 = 1
1/4 = 1/12 + 1/18 + 1/c
c = 9 days
c = 9 days
take total work as 1
work done by a in one day =( total work/total number of days taken) = 1/a = 1/12.
similarly work done by b and c are 1/b = 1/18 and 1/c respectively.
total work done by all three in one day = 1/12 + 1/18 + 1/c
(work done in one day × total number of days = total work )
[1/12 + 1/18 + 1/c] ×4 = 1
1/4 = 1/12 + 1/18 + 1/c
c = 9 days
ask16:
please mark this as branliest
your ans is wrong
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