Question

If a, b and c together can finish a piece of work in 4 days, a alone in 12 days and b in 18 days, then c alone can do it in how many days

Answer 1

C alone will complete the work in = [(2×4×12×18)÷(4×12-12×18+18×4)] days or
$20 \frac{4}{7} days$